By Berchie Holliday, Beatrice Luchin, Gilbert J. Cuevas

Holliday B., Luchin B., Cuevas G.J. California Algebra 2 (MGH Glencoe, 2007)(ISBN 0078778565)(O)(1133s)

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**Extra info for California Algebra 2 (MGH Glencoe, 2007)()(O)(1133s)**

**Example text**

5. c. Evaluate Fraction Bar The fraction bar acts as both an operation symbol, indicating division, and as a grouping symbol. Evaluate the expressions in the numerator and denominator separately before dividing. 5. 5) Find 82. 5. 25 from 64. a + 2bc _ if a = 2, b = -4, and c = -3. 3 c2 - 5 23 + 2(-4)(-3) a3 + 2bc _ __ = 2 2 c -5 (-3) - 5 8 + (-8)(-3) 9-5 a = 2, b = -4, and c = -3 = __ Evaluate the numerator and the denominator separately. =_ Multiply -8 by -3. 32 =_ or 8 Simplify the numerator and the denominator.

If a grade of at least 90 is an A, write an inequality to find the score Flavio must receive on the fifth test to have an A test average. 51. Solve the inequality and interpret the solution. Use a graphing calculator to solve each inequality. 52. -5x - 8 < 7 53. -4(6x - 3)≤ 60 54. 3(x + 3) ≥ 2(x + 4) 55. OPEN ENDED Write an inequality for which the solution set is the empty set. 56. REASONING Explain why it is not necessary to state a division property for inequalities. 57. CHALLENGE Which of the following properties hold for inequalities?

61. 61 for a. 76 = 76 ✔ Multiplication and Division Properties of Equality Example 4b could also have been solved using the Division Property of Equality. Note that dividing each side of 3 the equation by -_ is 5 the same as multiplying 5 . each side by -_ 3 3 b. -_ d = 18 5 3 d = 18 -_ 5 3 5 5 -_ -_ d = -_ (18) 3 3 5 ( ) d = -30 Simplify. Original equation Multiply each side by -_5 , the multiplicative inverse of -_3 . 3 Simplify. The solution is -30. 3 d = 18 -_ CHECK 5 3 -_ (-30) 18 5 18 = 18 ✔ Substitute -30 for d.